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The mkiv Supra Owners Club

My Dyno Result


ClaireRZ-S
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OK, so you have a car, it has 100bhp (flywheel) and it has 50% drivetrain losses.

 

It's rear wheel figure is 50% of 100 = 50bhp

 

Reversing the calculation, you were saying I have 50 rear wheel & 50% losses, so I add 50% of 50bhp (which is 25bhp) getting a total of 75bhp flywheel (which obviously isn;t what we started with).

 

What you need to do is divide the rwhp figure by (100 - the loss) as a percent.

 

So from our example rwhp / (100 - 50)

 

is 50 rwhp / 50 * 100 = 100 flywheel.

 

:)

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She got 337whp, say he didnt give her a fly figure. She comes on here is told 10-12% is a reasonable loss, so she gets picks a figure in that range say 11.86% of the whp, then adds it to the whp, does'nt that amount to the correct fly figure ! Using that the figures add up.

 

Dyno printout figures.

377fly 337whp 40 loss

 

Theory after not getting a fly figure from dyno operator.

(337/100)= 3.37 = 1% whp

3.37(1%) x 11.86 = 40

337+40 = 377 fly

 

Both match.

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So you're telling me the car has 333rwhp, but only a second ago you told me it started off with 337 rwhp. So we've lost 4bhp, where has that gone?

 

So it does'nt work in reverse but Ill never need to calculate whp, the dyno will do that :p and loss isnt a constant same % anyway, using 22.5% you wont lose 225 on a 1000bhp car !

Edited by Supra-Dupra (see edit history)
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Anyone fancy analysing my dyno printout from a while ago? i never understand them that much :p

 

Doesnt help the torque is in Nm, the guy who was doing the driving said it was the bigest torque figure he had seen on a bpu car. :S

And i lost 80 odd hp from the fly to the wheels. Is that reasonable?

BPU TT Auto UKspec btw.

 

Have to admit its not the best picture :p

 

engine - 383 bhp

wheel - 303 bhp

drag - 80

 

torque - 514nm

 

vbpgimage.php?do=full&p=9880&d=1198903778

Edited by Guigsy (see edit history)
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